3c^2-22c-16=0

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Solution for 3c^2-22c-16=0 equation: 


Simplifying
3c2 + -22c + -16 = 0

Reorder the terms:
-16 + -22c + 3c2 = 0

Solving
-16 + -22c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -3c)(8 + -1c) = 0


Subproblem 1
Set the factor '(-2 + -3c)' equal to zero and attempt to solve:

Simplifying
-2 + -3c = 0

Solving
-2 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -3c = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -3c = 0 + 2
-3c = 0 + 2

Combine like terms: 0 + 2 = 2
-3c = 2

Divide each side by '-3'.
c = -0.6666666667

Simplifying
c = -0.6666666667

Subproblem 2
Set the factor '(8 + -1c)' equal to zero and attempt to solve:

Simplifying
8 + -1c = 0

Solving
8 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1c = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1c = 0 + -8
-1c = 0 + -8

Combine like terms: 0 + -8 = -8
-1c = -8

Divide each side by '-1'.
c = 8

Simplifying
c = 8
Solution
c = {-0.6666666667, 8}

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